Solve for x 4(1-x)+2x=-3(x+1)

$4 (1 - x) + 2 x = - 3 (x + 1)$

Step 1

Simplify $4 (1 - x) + 2 x$ .

Simplify each term.

Apply the distributive property.

$4 \cdot 1 + 4 (- x) + 2 x = - 3 (x + 1)$

Multiply $4$ by $1$ .

$4 + 4 (- x) + 2 x = - 3 (x + 1)$

Multiply $- 1$ by $4$ .

$4 - 4 x + 2 x = - 3 (x + 1)$

Add $- 4 x$ and $2 x$ .

$4 - 2 x = - 3 (x + 1)$

Step 2

Simplify $- 3 (x + 1)$ .

Apply the distributive property.

$4 - 2 x = - 3 x - 3 \cdot 1$

Multiply $- 3$ by $1$ .

$4 - 2 x = - 3 x - 3$

Step 3

Move all terms containing $x$ to the left side of the equation.

Add $3 x$ to both sides of the equation.

$4 - 2 x + 3 x = - 3$

Add $- 2 x$ and $3 x$ .

$4 + x = - 3$

Step 4

Move all terms not containing $x$ to the right side of the equation.

Subtract $4$ from both sides of the equation.

$x = - 3 - 4$

Subtract $4$ from $- 3$ .

$x = - 7$