Solve for x 4^2=2(2+x)

$4^{2} = 2 (2 + x)$

Rewrite the equation as $2 (2 + x) = 4^{2}$ .

$2 (2 + x) = 4^{2}$

Divide each term in $2 (2 + x) = 4^{2}$ by $2$ and simplify.

Divide each term in $2 (2 + x) = 4^{2}$ by $2$ .

$\frac{2 (2 + x)}{2} = \frac{4^{2}}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 (2 + x)}{2} = \frac{4^{2}}{2}$

Divide $2 + x$ by $1$ .

$2 + x = \frac{4^{2}}{2}$

Simplify the right side.

Raise $4$ to the power of $2$ .

$2 + x = \frac{16}{2}$

Divide $16$ by $2$ .

$2 + x = 8$

Move all terms not containing $x$ to the right side of the equation.

Subtract $2$ from both sides of the equation.

$x = 8 - 2$

Subtract $2$ from $8$ .

$x = 6$