Solve for x 4(2+5(x-3))=8

$4 (2 + 5 (x - 3)) = 8$

Divide each term in $4 (2 + 5 (x - 3)) = 8$ by $4$ and simplify.

Divide each term in $4 (2 + 5 (x - 3)) = 8$ by $4$ .

$\frac{4 (2 + 5 (x - 3))}{4} = \frac{8}{4}$

Simplify the left side.

Cancel the common factor of $4$ .

Cancel the common factor.

$\frac{4 (2 + 5 (x - 3))}{4} = \frac{8}{4}$

Divide $2 + 5 (x - 3)$ by $1$ .

$2 + 5 (x - 3) = \frac{8}{4}$

Simplify each term.

Apply the distributive property.

$2 + 5 x + 5 \cdot - 3 = \frac{8}{4}$

Multiply $5$ by $- 3$ .

$2 + 5 x - 15 = \frac{8}{4}$

Subtract $15$ from $2$ .

$5 x - 13 = \frac{8}{4}$

Simplify the right side.

Divide $8$ by $4$ .

$5 x - 13 = 2$

Move all terms not containing $x$ to the right side of the equation.

Add $13$ to both sides of the equation.

$5 x = 2 + 13$

Add $2$ and $13$ .

$5 x = 15$

Divide each term in $5 x = 15$ by $5$ and simplify.

Divide each term in $5 x = 15$ by $5$ .

$\frac{5 x}{5} = \frac{15}{5}$

Simplify the left side.

Cancel the common factor of $5$ .

Cancel the common factor.

$\frac{5 x}{5} = \frac{15}{5}$

Divide $x$ by $1$ .

$x = \frac{15}{5}$

Simplify the right side.

Divide $15$ by $5$ .

$x = 3$