Solve for x 4-2(x-5)=x-19

$4 - 2 (x - 5) = x - 19$

Step 1

Simplify $4 - 2 (x - 5)$ .

Simplify each term.

Apply the distributive property.

$4 - 2 x - 2 \cdot - 5 = x - 19$

Multiply $- 2$ by $- 5$ .

$4 - 2 x + 10 = x - 19$

Add $4$ and $10$ .

$- 2 x + 14 = x - 19$

Step 2

Move all terms containing $x$ to the left side of the equation.

Subtract $x$ from both sides of the equation.

$- 2 x + 14 - x = - 19$

Subtract $x$ from $- 2 x$ .

$- 3 x + 14 = - 19$

Step 3

Move all terms not containing $x$ to the right side of the equation.

Subtract $14$ from both sides of the equation.

$- 3 x = - 19 - 14$

Subtract $14$ from $- 19$ .

$- 3 x = - 33$

Step 4

Divide each term in $- 3 x = - 33$ by $- 3$ and simplify.

Divide each term in $- 3 x = - 33$ by $- 3$ .

$\frac{- 3 x}{- 3} = \frac{- 33}{- 3}$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 x}{- 3} = \frac{- 33}{- 3}$

Divide $x$ by $1$ .

$x = \frac{- 33}{- 3}$

Simplify the right side.

Divide $- 33$ by $- 3$ .

$x = 11$