Solve for x 4(-2x+1)=6-(2x-4)

$4 (- 2 x + 1) = 6 - (2 x - 4)$

Step 1

Simplify $4 (- 2 x + 1)$ .

Rewrite.

$0 + 0 + 4 (- 2 x + 1) = 6 - (2 x - 4)$

Simplify by adding zeros.

$4 (- 2 x + 1) = 6 - (2 x - 4)$

Apply the distributive property.

$4 (- 2 x) + 4 \cdot 1 = 6 - (2 x - 4)$

Multiply.

Multiply $- 2$ by $4$ .

$- 8 x + 4 \cdot 1 = 6 - (2 x - 4)$

Multiply $4$ by $1$ .

$- 8 x + 4 = 6 - (2 x - 4)$

Step 2

Simplify $6 - (2 x - 4)$ .

Simplify each term.

Apply the distributive property.

$- 8 x + 4 = 6 - (2 x) - - 4$

Multiply $2$ by $- 1$ .

$- 8 x + 4 = 6 - 2 x - - 4$

Multiply $- 1$ by $- 4$ .

$- 8 x + 4 = 6 - 2 x + 4$

Add $6$ and $4$ .

$- 8 x + 4 = - 2 x + 10$

Step 3

Move all terms containing $x$ to the left side of the equation.

Add $2 x$ to both sides of the equation.

$- 8 x + 4 + 2 x = 10$

Add $- 8 x$ and $2 x$ .

$- 6 x + 4 = 10$

Step 4

Move all terms not containing $x$ to the right side of the equation.

Subtract $4$ from both sides of the equation.

$- 6 x = 10 - 4$

Subtract $4$ from $10$ .

$- 6 x = 6$

Step 5

Divide each term in $- 6 x = 6$ by $- 6$ and simplify.

Divide each term in $- 6 x = 6$ by $- 6$ .

$\frac{- 6 x}{- 6} = \frac{6}{- 6}$

Simplify the left side.

Cancel the common factor of $- 6$ .

Cancel the common factor.

$\frac{- 6 x}{- 6} = \frac{6}{- 6}$

Divide $x$ by $1$ .

$x = \frac{6}{- 6}$

Simplify the right side.

Divide $6$ by $- 6$ .

$x = - 1$

Solve for x 4(-2x+1)=6-(2x-4)

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