Solve for x 4(2x-3)+4=8x-8

$4 (2 x - 3) + 4 = 8 x - 8$

Step 1

Simplify $4 (2 x - 3) + 4$ .

Simplify each term.

Apply the distributive property.

$4 (2 x) + 4 \cdot - 3 + 4 = 8 x - 8$

Multiply $2$ by $4$ .

$8 x + 4 \cdot - 3 + 4 = 8 x - 8$

Multiply $4$ by $- 3$ .

$8 x - 12 + 4 = 8 x - 8$

Add $- 12$ and $4$ .

$8 x - 8 = 8 x - 8$

Step 2

Move all terms containing $x$ to the left side of the equation.

Subtract $8 x$ from both sides of the equation.

$8 x - 8 - 8 x = - 8$

Combine the opposite terms in $8 x - 8 - 8 x$ .

Subtract $8 x$ from $8 x$ .

$0 - 8 = - 8$

Subtract $8$ from $0$ .

$- 8 = - 8$

Step 3

Since $- 8 = - 8$ , the equation will always be true for any value of $x$ .

All real numbers

Step 4

The result can be shown in multiple forms.

All real numbers

Interval Notation:

$(- \infty, \infty)$