Solve for x 4(2x-(3-x)+5)=-6x-28

$4 (2 x - (3 - x) + 5) = - 6 x - 28$

Simplify $4 (2 x - (3 - x) + 5)$ .

Rewrite.

$0 + 0 + 4 (2 x - (3 - x) + 5) = - 6 x - 28$

Simplify by adding zeros.

$4 (2 x - (3 - x) + 5) = - 6 x - 28$

Simplify each term.

Apply the distributive property.

$4 (2 x - 1 \cdot 3 - - x + 5) = - 6 x - 28$

Multiply $- 1$ by $3$ .

$4 (2 x - 3 - - x + 5) = - 6 x - 28$

Multiply $- - x$ .

Multiply $- 1$ by $- 1$ .

$4 (2 x - 3 + 1 x + 5) = - 6 x - 28$

Multiply $x$ by $1$ .

$4 (2 x - 3 + x + 5) = - 6 x - 28$

Simplify terms.

Add $2 x$ and $x$ .

$4 (3 x - 3 + 5) = - 6 x - 28$

Add $- 3$ and $5$ .

$4 (3 x + 2) = - 6 x - 28$

Apply the distributive property.

$4 (3 x) + 4 \cdot 2 = - 6 x - 28$

Multiply.

Multiply $3$ by $4$ .

$12 x + 4 \cdot 2 = - 6 x - 28$

Multiply $4$ by $2$ .

$12 x + 8 = - 6 x - 28$

Move all terms containing $x$ to the left side of the equation.

Add $6 x$ to both sides of the equation.

$12 x + 8 + 6 x = - 28$

Add $12 x$ and $6 x$ .

$18 x + 8 = - 28$

Move all terms not containing $x$ to the right side of the equation.

Subtract $8$ from both sides of the equation.

$18 x = - 28 - 8$

Subtract $8$ from $- 28$ .

$18 x = - 36$

Divide each term in $18 x = - 36$ by $18$ and simplify.

Divide each term in $18 x = - 36$ by $18$ .

$\frac{18 x}{18} = \frac{- 36}{18}$

Simplify the left side.

Cancel the common factor of $18$ .

Cancel the common factor.

$\frac{18 x}{18} = \frac{- 36}{18}$

Divide $x$ by $1$ .

$x = \frac{- 36}{18}$

Simplify the right side.

Divide $- 36$ by $18$ .

$x = - 2$

Solve for x 4(2x-(3-x)+5)=-6x-28

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