Solve for x 4(2x-5)-3(x-5)=0

$4 (2 x - 5) - 3 (x - 5) = 0$

Step 1

Simplify $4 (2 x - 5) - 3 (x - 5)$ .

Simplify each term.

Apply the distributive property.

$4 (2 x) + 4 \cdot - 5 - 3 (x - 5) = 0$

Multiply $2$ by $4$ .

$8 x + 4 \cdot - 5 - 3 (x - 5) = 0$

Multiply $4$ by $- 5$ .

$8 x - 20 - 3 (x - 5) = 0$

Apply the distributive property.

$8 x - 20 - 3 x - 3 \cdot - 5 = 0$

Multiply $- 3$ by $- 5$ .

$8 x - 20 - 3 x + 15 = 0$

$8 x - 20 - 3 x + 15 = 0$

Simplify by adding terms.

Subtract $3 x$ from $8 x$ .

$5 x - 20 + 15 = 0$

Add $- 20$ and $15$ .

$5 x - 5 = 0$

$5 x - 5 = 0$

$5 x - 5 = 0$

Step 2

Add $5$ to both sides of the equation.

$5 x = 5$

Step 3

Divide each term in $5 x = 5$ by $5$ and simplify.

Divide each term in $5 x = 5$ by $5$ .

$\frac{5 x}{5} = \frac{5}{5}$

Simplify the left side.

Cancel the common factor of $5$ .

Cancel the common factor.

$\frac{5 x}{5} = \frac{5}{5}$

Divide $x$ by $1$ .

$x = \frac{5}{5}$

$x = \frac{5}{5}$

$x = \frac{5}{5}$

Simplify the right side.

Divide $5$ by $5$ .

$x = 1$

$x = 1$

$x = 1$

Related Questions