Solve for x 4=3/7(3x+14)

$4 = \frac{3}{7} (3 x + 14)$

Rewrite the equation as $\frac{3}{7} \cdot (3 x + 14) = 4$ .

$\frac{3}{7} \cdot (3 x + 14) = 4$

Multiply both sides of the equation by $\frac{7}{3}$ .

$\frac{7}{3} (\frac{3}{7} \cdot (3 x + 14)) = \frac{7}{3} \cdot 4$

Simplify both sides of the equation.

Simplify the left side.

Simplify $\frac{7}{3} (\frac{3}{7} \cdot (3 x + 14))$ .

Apply the distributive property.

$\frac{7}{3} (\frac{3}{7} (3 x) + \frac{3}{7} \cdot 14) = \frac{7}{3} \cdot 4$

Multiply $\frac{3}{7} (3 x)$ .

Combine $3$ and $\frac{3}{7}$ .

$\frac{7}{3} (\frac{3 \cdot 3}{7} x + \frac{3}{7} \cdot 14) = \frac{7}{3} \cdot 4$

Multiply $3$ by $3$ .

$\frac{7}{3} (\frac{9}{7} x + \frac{3}{7} \cdot 14) = \frac{7}{3} \cdot 4$

Combine $\frac{9}{7}$ and $x$ .

$\frac{7}{3} (\frac{9 x}{7} + \frac{3}{7} \cdot 14) = \frac{7}{3} \cdot 4$

Cancel the common factor of $7$ .

Factor $7$ out of $14$ .

$\frac{7}{3} (\frac{9 x}{7} + \frac{3}{7} \cdot (7 (2))) = \frac{7}{3} \cdot 4$

Cancel the common factor.

$\frac{7}{3} (\frac{9 x}{7} + \frac{3}{7} \cdot (7 \cdot 2)) = \frac{7}{3} \cdot 4$

Rewrite the expression.

$\frac{7}{3} (\frac{9 x}{7} + 3 \cdot 2) = \frac{7}{3} \cdot 4$

Multiply $3$ by $2$ .

$\frac{7}{3} (\frac{9 x}{7} + 6) = \frac{7}{3} \cdot 4$

Apply the distributive property.

$\frac{7}{3} \cdot \frac{9 x}{7} + \frac{7}{3} \cdot 6 = \frac{7}{3} \cdot 4$

Cancel the common factor of $7$ .

Cancel the common factor.

$\frac{7}{3} \cdot \frac{9 x}{7} + \frac{7}{3} \cdot 6 = \frac{7}{3} \cdot 4$

Rewrite the expression.

$\frac{1}{3} (9 x) + \frac{7}{3} \cdot 6 = \frac{7}{3} \cdot 4$

Cancel the common factor of $3$ .

Factor $3$ out of $9 x$ .

$\frac{1}{3} (3 (3 x)) + \frac{7}{3} \cdot 6 = \frac{7}{3} \cdot 4$

Cancel the common factor.

$\frac{1}{3} (3 (3 x)) + \frac{7}{3} \cdot 6 = \frac{7}{3} \cdot 4$

Rewrite the expression.

$3 x + \frac{7}{3} \cdot 6 = \frac{7}{3} \cdot 4$

Cancel the common factor of $3$ .

Factor $3$ out of $6$ .

$3 x + \frac{7}{3} \cdot (3 (2)) = \frac{7}{3} \cdot 4$

Cancel the common factor.

$3 x + \frac{7}{3} \cdot (3 \cdot 2) = \frac{7}{3} \cdot 4$

Rewrite the expression.

$3 x + 7 \cdot 2 = \frac{7}{3} \cdot 4$

Multiply $7$ by $2$ .

$3 x + 14 = \frac{7}{3} \cdot 4$

Simplify the right side.

Multiply $\frac{7}{3} \cdot 4$ .

Combine $\frac{7}{3}$ and $4$ .

$3 x + 14 = \frac{7 \cdot 4}{3}$

Multiply $7$ by $4$ .

$3 x + 14 = \frac{28}{3}$

Move all terms not containing $x$ to the right side of the equation.

Subtract $14$ from both sides of the equation.

$3 x = \frac{28}{3} - 14$

To write $- 14$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$3 x = \frac{28}{3} - 14 \cdot \frac{3}{3}$

Combine $- 14$ and $\frac{3}{3}$ .

$3 x = \frac{28}{3} + \frac{- 14 \cdot 3}{3}$

Combine the numerators over the common denominator.

$3 x = \frac{28 - 14 \cdot 3}{3}$

Simplify the numerator.

Multiply $- 14$ by $3$ .

$3 x = \frac{28 - 42}{3}$

Subtract $42$ from $28$ .

$3 x = \frac{- 14}{3}$

Move the negative in front of the fraction.

$3 x = - \frac{14}{3}$

Divide each term in $3 x = - \frac{14}{3}$ by $3$ and simplify.

Divide each term in $3 x = - \frac{14}{3}$ by $3$ .

$\frac{3 x}{3} = \frac{- \frac{14}{3}}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 x}{3} = \frac{- \frac{14}{3}}{3}$

Divide $x$ by $1$ .

$x = \frac{- \frac{14}{3}}{3}$

Simplify the right side.

Multiply the numerator by the reciprocal of the denominator.

$x = - \frac{14}{3} \cdot \frac{1}{3}$

Multiply $- \frac{14}{3} \cdot \frac{1}{3}$ .

Multiply $\frac{1}{3}$ by $\frac{14}{3}$ .

$x = - \frac{14}{3 \cdot 3}$

Multiply $3$ by $3$ .

$x = - \frac{14}{9}$

The result can be shown in multiple forms.

Exact Form:

$x = - \frac{14}{9}$

Decimal Form:

$x = - 1.\overline{5}$

Mixed Number Form:

$x = - 1 \frac{5}{9}$

Solve for x 4=3/7(3x+14)

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