Solve for x 4(3+x)+x=x+4

$4 (3 + x) + x = x + 4$

Simplify $4 (3 + x) + x$ .

Simplify each term.

Apply the distributive property.

$4 \cdot 3 + 4 x + x = x + 4$

Multiply $4$ by $3$ .

$12 + 4 x + x = x + 4$

Add $4 x$ and $x$ .

$12 + 5 x = x + 4$

Move all terms containing $x$ to the left side of the equation.

Subtract $x$ from both sides of the equation.

$12 + 5 x - x = 4$

Subtract $x$ from $5 x$ .

$12 + 4 x = 4$

Move all terms not containing $x$ to the right side of the equation.

Subtract $12$ from both sides of the equation.

$4 x = 4 - 12$

Subtract $12$ from $4$ .

$4 x = - 8$

Divide each term in $4 x = - 8$ by $4$ and simplify.

Divide each term in $4 x = - 8$ by $4$ .

$\frac{4 x}{4} = \frac{- 8}{4}$

Simplify the left side.

Cancel the common factor of $4$ .

Cancel the common factor.

$\frac{4 x}{4} = \frac{- 8}{4}$

Divide $x$ by $1$ .

$x = \frac{- 8}{4}$

Simplify the right side.

Divide $- 8$ by $4$ .

$x = - 2$