Solve for x 4^(3x+1)=4^2

$4^{3 x + 1} = 4^{2}$

Step 1

Create equivalent expressions in the equation that all have equal bases.

$4^{3 x + 1} = 4^{2}$

Step 2

Since the bases are the same, then two expressions are only equal if the exponents are also equal.

$3 x + 1 = 2$

Step 3

Solve for $x$ .

Move all terms not containing $x$ to the right side of the equation.

Subtract $1$ from both sides of the equation.

$3 x = 2 - 1$

Subtract $1$ from $2$ .

$3 x = 1$

Divide each term in $3 x = 1$ by $3$ and simplify.

Divide each term in $3 x = 1$ by $3$ .

$\frac{3 x}{3} = \frac{1}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 x}{3} = \frac{1}{3}$

Divide $x$ by $1$ .

$x = \frac{1}{3}$

Step 4

The result can be shown in multiple forms.

Exact Form:

$x = \frac{1}{3}$

Decimal Form:

$x = 0.\overline{3}$