Solve for x -4(3x+1)+x-3=15

$- 4 (3 x + 1) + x - 3 = 15$

Step 1

Simplify $- 4 (3 x + 1) + x - 3$ .

Simplify each term.

Apply the distributive property.

$- 4 (3 x) - 4 \cdot 1 + x - 3 = 15$

Multiply $3$ by $- 4$ .

$- 12 x - 4 \cdot 1 + x - 3 = 15$

Multiply $- 4$ by $1$ .

$- 12 x - 4 + x - 3 = 15$

Simplify by adding terms.

Add $- 12 x$ and $x$ .

$- 11 x - 4 - 3 = 15$

Subtract $3$ from $- 4$ .

$- 11 x - 7 = 15$

Step 2

Move all terms not containing $x$ to the right side of the equation.

Add $7$ to both sides of the equation.

$- 11 x = 15 + 7$

Add $15$ and $7$ .

$- 11 x = 22$

Step 3

Divide each term in $- 11 x = 22$ by $- 11$ and simplify.

Divide each term in $- 11 x = 22$ by $- 11$ .

$\frac{- 11 x}{- 11} = \frac{22}{- 11}$

Simplify the left side.

Cancel the common factor of $- 11$ .

Cancel the common factor.

$\frac{- 11 x}{- 11} = \frac{22}{- 11}$

Divide $x$ by $1$ .

$x = \frac{22}{- 11}$

Simplify the right side.

Divide $22$ by $- 11$ .

$x = - 2$