Solve for x 4+3x+1-x=5+2x

$4 + 3 x + 1 - x = 5 + 2 x$

Simplify $4 + 3 x + 1 - x$ .

Add $4$ and $1$ .

$3 x + 5 - x = 5 + 2 x$

Subtract $x$ from $3 x$ .

$2 x + 5 = 5 + 2 x$

Move all terms containing $x$ to the left side of the equation.

Subtract $2 x$ from both sides of the equation.

$2 x + 5 - 2 x = 5$

Combine the opposite terms in $2 x + 5 - 2 x$ .

Subtract $2 x$ from $2 x$ .

$0 + 5 = 5$

Add $0$ and $5$ .

$5 = 5$

Since $5 = 5$ , the equation will always be true for any value of $x$ .

All real numbers

The result can be shown in multiple forms.

All real numbers

Interval Notation:

$(- \infty, \infty)$