Solve for x 4-3x=8-4x

$4 - 3 x = 8 - 4 x$

Move all terms containing $x$ to the left side of the equation.

Add $4 x$ to both sides of the equation.

$4 - 3 x + 4 x = 8$

Add $- 3 x$ and $4 x$ .

$4 + x = 8$

Move all terms not containing $x$ to the right side of the equation.

Subtract $4$ from both sides of the equation.

$x = 8 - 4$

Subtract $4$ from $8$ .

$x = 4$