Solve for x 4(4-x)+6x=x+16-4x

$4 (4 - x) + 6 x = x + 16 - 4 x$

Simplify $4 (4 - x) + 6 x$ .

Simplify each term.

Apply the distributive property.

$4 \cdot 4 + 4 (- x) + 6 x = x + 16 - 4 x$

Multiply $4$ by $4$ .

$16 + 4 (- x) + 6 x = x + 16 - 4 x$

Multiply $- 1$ by $4$ .

$16 - 4 x + 6 x = x + 16 - 4 x$

Add $- 4 x$ and $6 x$ .

$16 + 2 x = x + 16 - 4 x$

Subtract $4 x$ from $x$ .

$16 + 2 x = - 3 x + 16$

Move all terms containing $x$ to the left side of the equation.

Add $3 x$ to both sides of the equation.

$16 + 2 x + 3 x = 16$

Add $2 x$ and $3 x$ .

$16 + 5 x = 16$

Move all terms not containing $x$ to the right side of the equation.

Subtract $16$ from both sides of the equation.

$5 x = 16 - 16$

Subtract $16$ from $16$ .

$5 x = 0$

Divide each term in $5 x = 0$ by $5$ and simplify.

Divide each term in $5 x = 0$ by $5$ .

$\frac{5 x}{5} = \frac{0}{5}$

Simplify the left side.

Cancel the common factor of $5$ .

Cancel the common factor.

$\frac{5 x}{5} = \frac{0}{5}$

Divide $x$ by $1$ .

$x = \frac{0}{5}$

Simplify the right side.

Divide $0$ by $5$ .

$x = 0$