Solve for x -4-4(-x-1)=4(x-1)

$- 4 - 4 (- x - 1) = 4 (x - 1)$

Simplify $- 4 - 4 (- x - 1)$ .

Simplify each term.

Apply the distributive property.

$- 4 - 4 (- x) - 4 \cdot - 1 = 4 (x - 1)$

Multiply $- 1$ by $- 4$ .

$- 4 + 4 x - 4 \cdot - 1 = 4 (x - 1)$

Multiply $- 4$ by $- 1$ .

$- 4 + 4 x + 4 = 4 (x - 1)$

Combine the opposite terms in $- 4 + 4 x + 4$ .

Add $- 4$ and $4$ .

$4 x + 0 = 4 (x - 1)$

Add $4 x$ and $0$ .

$4 x = 4 (x - 1)$

Simplify $4 (x - 1)$ .

Apply the distributive property.

$4 x = 4 x + 4 \cdot - 1$

Multiply $4$ by $- 1$ .

$4 x = 4 x - 4$

Move all terms containing $x$ to the left side of the equation.

Subtract $4 x$ from both sides of the equation.

$4 x - 4 x = - 4$

Subtract $4 x$ from $4 x$ .

$0 = - 4$

Since $0 \neq - 4$ , there are no solutions.

No solution