Solve for x 4(5x+3)=14x+30

$4 (5 x + 3) = 14 x + 30$

Step 1

Simplify $4 (5 x + 3)$ .

Rewrite.

$0 + 0 + 4 (5 x + 3) = 14 x + 30$

Simplify by adding zeros.

$4 (5 x + 3) = 14 x + 30$

Apply the distributive property.

$4 (5 x) + 4 \cdot 3 = 14 x + 30$

Multiply.

Multiply $5$ by $4$ .

$20 x + 4 \cdot 3 = 14 x + 30$

Multiply $4$ by $3$ .

$20 x + 12 = 14 x + 30$

Step 2

Move all terms containing $x$ to the left side of the equation.

Subtract $14 x$ from both sides of the equation.

$20 x + 12 - 14 x = 30$

Subtract $14 x$ from $20 x$ .

$6 x + 12 = 30$

Step 3

Move all terms not containing $x$ to the right side of the equation.

Subtract $12$ from both sides of the equation.

$6 x = 30 - 12$

Subtract $12$ from $30$ .

$6 x = 18$

Step 4

Divide each term in $6 x = 18$ by $6$ and simplify.

Divide each term in $6 x = 18$ by $6$ .

$\frac{6 x}{6} = \frac{18}{6}$

Simplify the left side.

Cancel the common factor of $6$ .

Cancel the common factor.

$\frac{6 x}{6} = \frac{18}{6}$

Divide $x$ by $1$ .

$x = \frac{18}{6}$

Simplify the right side.

Divide $18$ by $6$ .

$x = 3$