Solve for x 4+6(2+x)=2(3x+8)

$4 + 6 (2 + x) = 2 (3 x + 8)$

Simplify $4 + 6 (2 + x)$ .

Simplify each term.

Apply the distributive property.

$4 + 6 \cdot 2 + 6 x = 2 (3 x + 8)$

Multiply $6$ by $2$ .

$4 + 12 + 6 x = 2 (3 x + 8)$

Add $4$ and $12$ .

$16 + 6 x = 2 (3 x + 8)$

Simplify $2 (3 x + 8)$ .

Apply the distributive property.

$16 + 6 x = 2 (3 x) + 2 \cdot 8$

Multiply.

Multiply $3$ by $2$ .

$16 + 6 x = 6 x + 2 \cdot 8$

Multiply $2$ by $8$ .

$16 + 6 x = 6 x + 16$

Move all terms containing $x$ to the left side of the equation.

Subtract $6 x$ from both sides of the equation.

$16 + 6 x - 6 x = 16$

Combine the opposite terms in $16 + 6 x - 6 x$ .

Subtract $6 x$ from $6 x$ .

$16 + 0 = 16$

Add $16$ and $0$ .

$16 = 16$

Since $16 = 16$ , the equation will always be true for any value of $x$ .

All real numbers

The result can be shown in multiple forms.

All real numbers

Interval Notation:

$(- \infty, \infty)$