Solve for x 4(6-x)-2(3-x)-5=9(5-2x)

$4 (6 - x) - 2 (3 - x) - 5 = 9 (5 - 2 x)$

Step 1

Simplify $4 (6 - x) - 2 (3 - x) - 5$ .

Simplify each term.

Apply the distributive property.

$4 \cdot 6 + 4 (- x) - 2 (3 - x) - 5 = 9 (5 - 2 x)$

Multiply $4$ by $6$ .

$24 + 4 (- x) - 2 (3 - x) - 5 = 9 (5 - 2 x)$

Multiply $- 1$ by $4$ .

$24 - 4 x - 2 (3 - x) - 5 = 9 (5 - 2 x)$

Apply the distributive property.

$24 - 4 x - 2 \cdot 3 - 2 (- x) - 5 = 9 (5 - 2 x)$

Multiply $- 2$ by $3$ .

$24 - 4 x - 6 - 2 (- x) - 5 = 9 (5 - 2 x)$

Multiply $- 1$ by $- 2$ .

$24 - 4 x - 6 + 2 x - 5 = 9 (5 - 2 x)$

Simplify by adding terms.

Subtract $6$ from $24$ .

$- 4 x + 18 + 2 x - 5 = 9 (5 - 2 x)$

Add $- 4 x$ and $2 x$ .

$- 2 x + 18 - 5 = 9 (5 - 2 x)$

Subtract $5$ from $18$ .

$- 2 x + 13 = 9 (5 - 2 x)$

Step 2

Simplify $9 (5 - 2 x)$ .

Apply the distributive property.

$- 2 x + 13 = 9 \cdot 5 + 9 (- 2 x)$

Multiply.

Multiply $9$ by $5$ .

$- 2 x + 13 = 45 + 9 (- 2 x)$

Multiply $- 2$ by $9$ .

$- 2 x + 13 = 45 - 18 x$

Step 3

Move all terms containing $x$ to the left side of the equation.

Add $18 x$ to both sides of the equation.

$- 2 x + 13 + 18 x = 45$

Add $- 2 x$ and $18 x$ .

$16 x + 13 = 45$

Step 4

Move all terms not containing $x$ to the right side of the equation.

Subtract $13$ from both sides of the equation.

$16 x = 45 - 13$

Subtract $13$ from $45$ .

$16 x = 32$

Step 5

Divide each term in $16 x = 32$ by $16$ and simplify.

Divide each term in $16 x = 32$ by $16$ .

$\frac{16 x}{16} = \frac{32}{16}$

Simplify the left side.

Cancel the common factor of $16$ .

Cancel the common factor.

$\frac{16 x}{16} = \frac{32}{16}$

Divide $x$ by $1$ .

$x = \frac{32}{16}$

Simplify the right side.

Divide $32$ by $16$ .

$x = 2$

Solve for x 4(6-x)-2(3-x)-5=9(5-2x)

Related Questions

Support LCMGCF.com by disabling your adblocker.