Solve for x 4-7x+10=15-6x-8

$4 - 7 x + 10 = 15 - 6 x - 8$

Step 1

Add $4$ and $10$ .

$- 7 x + 14 = 15 - 6 x - 8$

Step 2

Subtract $8$ from $15$ .

$- 7 x + 14 = - 6 x + 7$

Step 3

Move all terms containing $x$ to the left side of the equation.

Add $6 x$ to both sides of the equation.

$- 7 x + 14 + 6 x = 7$

Add $- 7 x$ and $6 x$ .

$- x + 14 = 7$

Step 4

Move all terms not containing $x$ to the right side of the equation.

Subtract $14$ from both sides of the equation.

$- x = 7 - 14$

Subtract $14$ from $7$ .

$- x = - 7$

Step 5

Divide each term in $- x = - 7$ by $- 1$ and simplify.

Divide each term in $- x = - 7$ by $- 1$ .

$\frac{- x}{- 1} = \frac{- 7}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{x}{1} = \frac{- 7}{- 1}$

Divide $x$ by $1$ .

$x = \frac{- 7}{- 1}$

Simplify the right side.

Divide $- 7$ by $- 1$ .

$x = 7$