Solve for x -4(x+1)-3=-3(x-4)

$- 4 (x + 1) - 3 = - 3 (x - 4)$

Step 1

Simplify $- 4 (x + 1) - 3$ .

Simplify each term.

Apply the distributive property.

$- 4 x - 4 \cdot 1 - 3 = - 3 (x - 4)$

Multiply $- 4$ by $1$ .

$- 4 x - 4 - 3 = - 3 (x - 4)$

Subtract $3$ from $- 4$ .

$- 4 x - 7 = - 3 (x - 4)$

Step 2

Simplify $- 3 (x - 4)$ .

Apply the distributive property.

$- 4 x - 7 = - 3 x - 3 \cdot - 4$

Multiply $- 3$ by $- 4$ .

$- 4 x - 7 = - 3 x + 12$

Step 3

Move all terms containing $x$ to the left side of the equation.

Add $3 x$ to both sides of the equation.

$- 4 x - 7 + 3 x = 12$

Add $- 4 x$ and $3 x$ .

$- x - 7 = 12$

Step 4

Move all terms not containing $x$ to the right side of the equation.

Add $7$ to both sides of the equation.

$- x = 12 + 7$

Add $12$ and $7$ .

$- x = 19$

Step 5

Divide each term in $- x = 19$ by $- 1$ and simplify.

Divide each term in $- x = 19$ by $- 1$ .

$\frac{- x}{- 1} = \frac{19}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{x}{1} = \frac{19}{- 1}$

Divide $x$ by $1$ .

$x = \frac{19}{- 1}$

Simplify the right side.

Divide $19$ by $- 1$ .

$x = - 19$