Solve for x 4(x+1)=4(2-x)

$4 (x + 1) = 4 (2 - x)$

Simplify $4 (x + 1)$ .

Start simplifying.

$0 + 0 + 4 (x + 1) = 4 (2 - x)$

Simplify by adding zeros.

$4 (x + 1) = 4 (2 - x)$

Apply the distributive property.

$4 x + 4 \cdot 1 = 4 (2 - x)$

Multiply $4$ by $1$ .

$4 x + 4 = 4 (2 - x)$

Simplify $4 (2 - x)$ .

Apply the distributive property.

$4 x + 4 = 4 \cdot 2 + 4 (- x)$

Multiply.

Multiply $4$ by $2$ .

$4 x + 4 = 8 + 4 (- x)$

Multiply $- 1$ by $4$ .

$4 x + 4 = 8 - 4 x$

Move all terms containing $x$ to the left side of the equation.

Add $4 x$ to both sides of the equation.

$4 x + 4 + 4 x = 8$

Add $4 x$ and $4 x$ .

$8 x + 4 = 8$

Move all terms not containing $x$ to the right side of the equation.

Subtract $4$ from both sides of the equation.

$8 x = 8 - 4$

Subtract $4$ from $8$ .

$8 x = 4$

Divide each term in $8 x = 4$ by $8$ and simplify.

Divide each term in $8 x = 4$ by $8$ .

$\frac{8 x}{8} = \frac{4}{8}$

Simplify the left side.

Cancel the common factor of $8$ .

Cancel the common factor.

$\frac{8 x}{8} = \frac{4}{8}$

Divide $x$ by $1$ .

$x = \frac{4}{8}$

Simplify the right side.

Cancel the common factor of $4$ and $8$ .

Factor $4$ out of $4$ .

$x = \frac{4 (1)}{8}$

Cancel the common factors.

Factor $4$ out of $8$ .

$x = \frac{4 \cdot 1}{4 \cdot 2}$

Cancel the common factor.

$x = \frac{4 \cdot 1}{4 \cdot 2}$

Rewrite the expression.

$x = \frac{1}{2}$

The result can be shown in multiple forms.

Exact Form:

$x = \frac{1}{2}$

Decimal Form:

$x = 0.5$

Solve for x 4(x+1)=4(2-x)

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