Solve for x 4/(x+2)=(x^2)/(x+2)

$\frac{4}{x + 2} = \frac{x^{2}}{x + 2}$

Step 1

Since the expression on each side of the equation has the same denominator, the numerators must be equal.

$4 = x^{2}$

Step 2

Rewrite the equation as $x^{2} = 4$ .

$x^{2} = 4$

Step 3

Take the square root of both sides of the equation to eliminate the exponent on the left side.

$x = \pm \sqrt{4}$

Step 4

Simplify $\pm \sqrt{4}$ .

Rewrite $4$ as $2^{2}$ .

$x = \pm \sqrt{2^{2}}$

Pull terms out from under the radical, assuming positive real numbers.

$x = \pm 2$

Step 5

The complete solution is the result of both the positive and negative portions of the solution.

First, use the positive value of the $\pm$ to find the first solution.

$x = 2$

Next, use the negative value of the $\pm$ to find the second solution.

$x = - 2$

The complete solution is the result of both the positive and negative portions of the solution.

$x = 2, - 2$

Step 6

Exclude the solutions that do not make $\frac{4}{x + 2} = \frac{x^{2}}{x + 2}$ true.

$x = 2$