Solve for x -4(x+2)+x=3x-8-5x

$- 4 (x + 2) + x = 3 x - 8 - 5 x$

Step 1

Simplify $- 4 (x + 2) + x$ .

Simplify each term.

Apply the distributive property.

$- 4 x - 4 \cdot 2 + x = 3 x - 8 - 5 x$

Multiply $- 4$ by $2$ .

$- 4 x - 8 + x = 3 x - 8 - 5 x$

Add $- 4 x$ and $x$ .

$- 3 x - 8 = 3 x - 8 - 5 x$

Step 2

Subtract $5 x$ from $3 x$ .

$- 3 x - 8 = - 2 x - 8$

Step 3

Move all terms containing $x$ to the left side of the equation.

Add $2 x$ to both sides of the equation.

$- 3 x - 8 + 2 x = - 8$

Add $- 3 x$ and $2 x$ .

$- x - 8 = - 8$

Step 4

Move all terms not containing $x$ to the right side of the equation.

Add $8$ to both sides of the equation.

$- x = - 8 + 8$

Add $- 8$ and $8$ .

$- x = 0$

Step 5

Divide each term in $- x = 0$ by $- 1$ and simplify.

Divide each term in $- x = 0$ by $- 1$ .

$\frac{- x}{- 1} = \frac{0}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{x}{1} = \frac{0}{- 1}$

Divide $x$ by $1$ .

$x = \frac{0}{- 1}$

Simplify the right side.

Divide $0$ by $- 1$ .

$x = 0$