Solve for x -(4+x)/3=-2

$- \frac{4 + x}{3} = - 2$

Step 1

Multiply both sides of the equation by $- 3$ .

$- 3 (- \frac{4 + x}{3}) = - 3 \cdot - 2$

Step 2

Simplify both sides of the equation.

Simplify the left side.

Simplify $- 3 (- \frac{4 + x}{3})$ .

Cancel the common factor of $3$ .

Move the leading negative in $- \frac{4 + x}{3}$ into the numerator.

$- 3 \frac{- (4 + x)}{3} = - 3 \cdot - 2$

Factor $3$ out of $- 3$ .

$3 (- 1) \frac{- (4 + x)}{3} = - 3 \cdot - 2$

Cancel the common factor.

$3 \cdot - 1 \frac{- (4 + x)}{3} = - 3 \cdot - 2$

Rewrite the expression.

$- - (4 + x) = - 3 \cdot - 2$

Multiply.

Multiply $- 1$ by $- 1$ .

$1 (4 + x) = - 3 \cdot - 2$

Multiply $4 + x$ by $1$ .

$4 + x = - 3 \cdot - 2$

Simplify the right side.

Multiply $- 3$ by $- 2$ .

$4 + x = 6$

Step 3

Move all terms not containing $x$ to the right side of the equation.

Subtract $4$ from both sides of the equation.

$x = 6 - 4$

Subtract $4$ from $6$ .

$x = 2$