Solve for x 4(x-3)>=25

$4 (x - 3) \geq 25$

Divide each term in $4 (x - 3) \geq 25$ by $4$ and simplify.

Divide each term in $4 (x - 3) \geq 25$ by $4$ .

$\frac{4 (x - 3)}{4} \geq \frac{25}{4}$

Simplify the left side.

Cancel the common factor of $4$ .

Cancel the common factor.

$\frac{4 (x - 3)}{4} \geq \frac{25}{4}$

Divide $x - 3$ by $1$ .

$x - 3 \geq \frac{25}{4}$

Move all terms not containing $x$ to the right side of the inequality.

Add $3$ to both sides of the inequality.

$x \geq \frac{25}{4} + 3$

To write $3$ as a fraction with a common denominator, multiply by $\frac{4}{4}$ .

$x \geq \frac{25}{4} + 3 \cdot \frac{4}{4}$

Combine $3$ and $\frac{4}{4}$ .

$x \geq \frac{25}{4} + \frac{3 \cdot 4}{4}$

Combine the numerators over the common denominator.

$x \geq \frac{25 + 3 \cdot 4}{4}$

Simplify the numerator.

Multiply $3$ by $4$ .

$x \geq \frac{25 + 12}{4}$

Add $25$ and $12$ .

$x \geq \frac{37}{4}$

The result can be shown in multiple forms.

Inequality Form:

$x \geq \frac{37}{4}$

Interval Notation:

$[\frac{37}{4}, \infty)$