Solve for x 4-x-3=6-x-2

$4 - x - 3 = 6 - x - 2$

Subtract $3$ from $4$ .

$- x + 1 = 6 - x - 2$

Subtract $2$ from $6$ .

$- x + 1 = - x + 4$

Move all terms containing $x$ to the left side of the equation.

Add $x$ to both sides of the equation.

$- x + 1 + x = 4$

Combine the opposite terms in $- x + 1 + x$ .

Add $- x$ and $x$ .

$0 + 1 = 4$

Add $0$ and $1$ .

$1 = 4$

Since $1 \neq 4$ , there are no solutions.

No solution