Solve for x 4+(x-3)/8=12

$4 + \frac{x - 3}{8} = 12$

Simplify $4 + \frac{x - 3}{8}$ .

To write $4$ as a fraction with a common denominator, multiply by $\frac{8}{8}$ .

$4 \cdot \frac{8}{8} + \frac{x - 3}{8} = 12$

Simplify terms.

Combine $4$ and $\frac{8}{8}$ .

$\frac{4 \cdot 8}{8} + \frac{x - 3}{8} = 12$

Combine the numerators over the common denominator.

$\frac{4 \cdot 8 + x - 3}{8} = 12$

Simplify the numerator.

Multiply $4$ by $8$ .

$\frac{32 + x - 3}{8} = 12$

Subtract $3$ from $32$ .

$\frac{x + 29}{8} = 12$

Multiply both sides of the equation by $8$ .

$8 \frac{x + 29}{8} = 8 \cdot 12$

Simplify both sides of the equation.

Simplify the left side.

Cancel the common factor of $8$ .

Cancel the common factor.

$8 \frac{x + 29}{8} = 8 \cdot 12$

Rewrite the expression.

$x + 29 = 8 \cdot 12$

Simplify the right side.

Multiply $8$ by $12$ .

$x + 29 = 96$

Move all terms not containing $x$ to the right side of the equation.

Subtract $29$ from both sides of the equation.

$x = 96 - 29$

Subtract $29$ from $96$ .

$x = 67$