Solve for x 4(x+4)=6(x-2)

$4 (x + 4) = 6 (x - 2)$

Step 1

Simplify $4 (x + 4)$ .

Rewrite.

$0 + 0 + 4 (x + 4) = 6 (x - 2)$

Simplify by adding zeros.

$4 (x + 4) = 6 (x - 2)$

Apply the distributive property.

$4 x + 4 \cdot 4 = 6 (x - 2)$

Multiply $4$ by $4$ .

$4 x + 16 = 6 (x - 2)$

Step 2

Simplify $6 (x - 2)$ .

Apply the distributive property.

$4 x + 16 = 6 x + 6 \cdot - 2$

Multiply $6$ by $- 2$ .

$4 x + 16 = 6 x - 12$

Step 3

Move all terms containing $x$ to the left side of the equation.

Subtract $6 x$ from both sides of the equation.

$4 x + 16 - 6 x = - 12$

Subtract $6 x$ from $4 x$ .

$- 2 x + 16 = - 12$

Step 4

Move all terms not containing $x$ to the right side of the equation.

Subtract $16$ from both sides of the equation.

$- 2 x = - 12 - 16$

Subtract $16$ from $- 12$ .

$- 2 x = - 28$

Step 5

Divide each term in $- 2 x = - 28$ by $- 2$ and simplify.

Divide each term in $- 2 x = - 28$ by $- 2$ .

$\frac{- 2 x}{- 2} = \frac{- 28}{- 2}$

Simplify the left side.

Cancel the common factor of $- 2$ .

Cancel the common factor.

$\frac{- 2 x}{- 2} = \frac{- 28}{- 2}$

Divide $x$ by $1$ .

$x = \frac{- 28}{- 2}$

Simplify the right side.

Divide $- 28$ by $- 2$ .

$x = 14$