Solve for x -4(x+4x)=2(2-x)+10

$- 4 (x + 4 x) = 2 (2 - x) + 10$

Step 1

Simplify $- 4 (x + 4 x)$ .

Rewrite.

$0 + 0 - 4 (x + 4 x) = 2 (2 - x) + 10$

Simplify by adding zeros.

$- 4 (x + 4 x) = 2 (2 - x) + 10$

Add $x$ and $4 x$ .

$- 4 (5 x) = 2 (2 - x) + 10$

Multiply $5$ by $- 4$ .

$- 20 x = 2 (2 - x) + 10$

Step 2

Simplify $2 (2 - x) + 10$ .

Simplify each term.

Apply the distributive property.

$- 20 x = 2 \cdot 2 + 2 (- x) + 10$

Multiply $2$ by $2$ .

$- 20 x = 4 + 2 (- x) + 10$

Multiply $- 1$ by $2$ .

$- 20 x = 4 - 2 x + 10$

Add $4$ and $10$ .

$- 20 x = - 2 x + 14$

Step 3

Move all terms containing $x$ to the left side of the equation.

Add $2 x$ to both sides of the equation.

$- 20 x + 2 x = 14$

Add $- 20 x$ and $2 x$ .

$- 18 x = 14$

Step 4

Divide each term in $- 18 x = 14$ by $- 18$ and simplify.

Divide each term in $- 18 x = 14$ by $- 18$ .

$\frac{- 18 x}{- 18} = \frac{14}{- 18}$

Simplify the left side.

Cancel the common factor of $- 18$ .

Cancel the common factor.

$\frac{- 18 x}{- 18} = \frac{14}{- 18}$

Divide $x$ by $1$ .

$x = \frac{14}{- 18}$

Simplify the right side.

Cancel the common factor of $14$ and $- 18$ .

Factor $2$ out of $14$ .

$x = \frac{2 (7)}{- 18}$

Cancel the common factors.

Factor $2$ out of $- 18$ .

$x = \frac{2 \cdot 7}{2 \cdot - 9}$

Cancel the common factor.

$x = \frac{2 \cdot 7}{2 \cdot - 9}$

Rewrite the expression.

$x = \frac{7}{- 9}$

Move the negative in front of the fraction.

$x = - \frac{7}{9}$

Step 5

The result can be shown in multiple forms.

Exact Form:

$x = - \frac{7}{9}$

Decimal Form:

$x = - 0.\overline{7}$

Solve for x -4(x+4x)=2(2-x)+10

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