Solve for x 4(x/6+5)=2x+10

$4 (\frac{x}{6} + 5) = 2 x + 10$

Simplify $4 (\frac{x}{6} + 5)$ .

Rewrite.

$0 + 0 + 4 (\frac{x}{6} + 5) = 2 x + 10$

Simplify by adding zeros.

$4 (\frac{x}{6} + 5) = 2 x + 10$

Apply the distributive property.

$4 \frac{x}{6} + 4 \cdot 5 = 2 x + 10$

Cancel the common factor of $2$ .

Factor $2$ out of $4$ .

$2 (2) \frac{x}{6} + 4 \cdot 5 = 2 x + 10$

Factor $2$ out of $6$ .

$2 \cdot 2 \frac{x}{2 \cdot 3} + 4 \cdot 5 = 2 x + 10$

Cancel the common factor.

$2 \cdot 2 \frac{x}{2 \cdot 3} + 4 \cdot 5 = 2 x + 10$

Rewrite the expression.

$2 \frac{x}{3} + 4 \cdot 5 = 2 x + 10$

Combine $2$ and $\frac{x}{3}$ .

$\frac{2 x}{3} + 4 \cdot 5 = 2 x + 10$

Multiply $4$ by $5$ .

$\frac{2 x}{3} + 20 = 2 x + 10$

Move all terms containing $x$ to the left side of the equation.

Subtract $2 x$ from both sides of the equation.

$\frac{2 x}{3} + 20 - 2 x = 10$

To write $- 2 x$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$\frac{2 x}{3} - 2 x \cdot \frac{3}{3} + 20 = 10$

Combine $- 2 x$ and $\frac{3}{3}$ .

$\frac{2 x}{3} + \frac{- 2 x \cdot 3}{3} + 20 = 10$

Combine the numerators over the common denominator.

$\frac{2 x - 2 x \cdot 3}{3} + 20 = 10$

Simplify each term.

Simplify the numerator.

Factor $2 x$ out of $2 x - 2 x \cdot 3$ .

Factor $2 x$ out of $2 x$ .

$\frac{2 x (1) - 2 x \cdot 3}{3} + 20 = 10$

Factor $2 x$ out of $- 2 x \cdot 3$ .

$\frac{2 x (1) + 2 x (- 1 \cdot 3)}{3} + 20 = 10$

Factor $2 x$ out of $2 x (1) + 2 x (- 1 \cdot 3)$ .

$\frac{2 x (1 - 1 \cdot 3)}{3} + 20 = 10$

Multiply $- 1$ by $3$ .

$\frac{2 x (1 - 3)}{3} + 20 = 10$

Subtract $3$ from $1$ .

$\frac{2 x \cdot - 2}{3} + 20 = 10$

Multiply $- 2$ by $2$ .

$\frac{- 4 x}{3} + 20 = 10$

Move the negative in front of the fraction.

$- \frac{4 x}{3} + 20 = 10$

Move all terms not containing $x$ to the right side of the equation.

Subtract $20$ from both sides of the equation.

$- \frac{4 x}{3} = 10 - 20$

Subtract $20$ from $10$ .

$- \frac{4 x}{3} = - 10$

Multiply both sides of the equation by $- \frac{3}{4}$ .

$- \frac{3}{4} (- \frac{4 x}{3}) = - \frac{3}{4} \cdot - 10$

Simplify both sides of the equation.

Simplify the left side.

Simplify $- \frac{3}{4} (- \frac{4 x}{3})$ .

Cancel the common factor of $3$ .

Move the leading negative in $- \frac{3}{4}$ into the numerator.

$\frac{- 3}{4} (- \frac{4 x}{3}) = - \frac{3}{4} \cdot - 10$

Move the leading negative in $- \frac{4 x}{3}$ into the numerator.

$\frac{- 3}{4} \cdot \frac{- 4 x}{3} = - \frac{3}{4} \cdot - 10$

Factor $3$ out of $- 3$ .

$\frac{3 (- 1)}{4} \cdot \frac{- 4 x}{3} = - \frac{3}{4} \cdot - 10$

Cancel the common factor.

$\frac{3 \cdot - 1}{4} \cdot \frac{- 4 x}{3} = - \frac{3}{4} \cdot - 10$

Rewrite the expression.

$\frac{- 1}{4} (- 4 x) = - \frac{3}{4} \cdot - 10$

Cancel the common factor of $4$ .

Factor $4$ out of $- 4 x$ .

$\frac{- 1}{4} (4 (- x)) = - \frac{3}{4} \cdot - 10$

Cancel the common factor.

$\frac{- 1}{4} (4 (- x)) = - \frac{3}{4} \cdot - 10$

Rewrite the expression.

$- - x = - \frac{3}{4} \cdot - 10$

Multiply.

Multiply $- 1$ by $- 1$ .

$1 x = - \frac{3}{4} \cdot - 10$

Multiply $x$ by $1$ .

$x = - \frac{3}{4} \cdot - 10$

Simplify the right side.

Simplify $- \frac{3}{4} \cdot - 10$ .

Cancel the common factor of $2$ .

Move the leading negative in $- \frac{3}{4}$ into the numerator.

$x = \frac{- 3}{4} \cdot - 10$

Factor $2$ out of $4$ .

$x = \frac{- 3}{2 (2)} \cdot - 10$

Factor $2$ out of $- 10$ .

$x = \frac{- 3}{2 \cdot 2} \cdot (2 \cdot - 5)$

Cancel the common factor.

$x = \frac{- 3}{2 \cdot 2} \cdot (2 \cdot - 5)$

Rewrite the expression.

$x = \frac{- 3}{2} \cdot - 5$

Combine $\frac{- 3}{2}$ and $- 5$ .

$x = \frac{- 3 \cdot - 5}{2}$

Multiply $- 3$ by $- 5$ .

$x = \frac{15}{2}$

The result can be shown in multiple forms.

Exact Form:

$x = \frac{15}{2}$

Decimal Form:

$x = 7.5$

Mixed Number Form:

$x = 7 \frac{1}{2}$

Solve for x 4(x/6+5)=2x+10

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