Solve for x 40=-1/3(9x+30)+2

$40 = - \frac{1}{3} (9 x + 30) + 2$

Rewrite the equation as $- \frac{1}{3} \cdot (9 x + 30) + 2 = 40$ .

$- \frac{1}{3} \cdot (9 x + 30) + 2 = 40$

Simplify $- \frac{1}{3} \cdot (9 x + 30) + 2$ .

Simplify each term.

Apply the distributive property.

$- \frac{1}{3} (9 x) - \frac{1}{3} \cdot 30 + 2 = 40$

Cancel the common factor of $3$ .

Move the leading negative in $- \frac{1}{3}$ into the numerator.

$\frac{- 1}{3} (9 x) - \frac{1}{3} \cdot 30 + 2 = 40$

Factor $3$ out of $9 x$ .

$\frac{- 1}{3} (3 (3 x)) - \frac{1}{3} \cdot 30 + 2 = 40$

Cancel the common factor.

$\frac{- 1}{3} (3 (3 x)) - \frac{1}{3} \cdot 30 + 2 = 40$

Rewrite the expression.

$- 1 (3 x) - \frac{1}{3} \cdot 30 + 2 = 40$

Multiply $3$ by $- 1$ .

$- 3 x - \frac{1}{3} \cdot 30 + 2 = 40$

Cancel the common factor of $3$ .

Move the leading negative in $- \frac{1}{3}$ into the numerator.

$- 3 x + \frac{- 1}{3} \cdot 30 + 2 = 40$

Factor $3$ out of $30$ .

$- 3 x + \frac{- 1}{3} \cdot (3 (10)) + 2 = 40$

Cancel the common factor.

$- 3 x + \frac{- 1}{3} \cdot (3 \cdot 10) + 2 = 40$

Rewrite the expression.

$- 3 x - 1 \cdot 10 + 2 = 40$

Multiply $- 1$ by $10$ .

$- 3 x - 10 + 2 = 40$

Add $- 10$ and $2$ .

$- 3 x - 8 = 40$

Move all terms not containing $x$ to the right side of the equation.

Add $8$ to both sides of the equation.

$- 3 x = 40 + 8$

Add $40$ and $8$ .

$- 3 x = 48$

Divide each term in $- 3 x = 48$ by $- 3$ and simplify.

Divide each term in $- 3 x = 48$ by $- 3$ .

$\frac{- 3 x}{- 3} = \frac{48}{- 3}$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 x}{- 3} = \frac{48}{- 3}$

Divide $x$ by $1$ .

$x = \frac{48}{- 3}$

Simplify the right side.

Divide $48$ by $- 3$ .

$x = - 16$

Solve for x 40=-1/3(9x+30)+2

Related Questions

Support LCMGCF.com by disabling your adblocker.