Solve for x 40-8x=-8(x-5)

$40 - 8 x = - 8 (x - 5)$

Simplify $- 8 (x - 5)$ .

Rewrite.

$40 - 8 x = 0 + 0 - 8 (x - 5)$

Simplify by adding zeros.

$40 - 8 x = - 8 (x - 5)$

Apply the distributive property.

$40 - 8 x = - 8 x - 8 \cdot - 5$

Multiply $- 8$ by $- 5$ .

$40 - 8 x = - 8 x + 40$

Move all terms containing $x$ to the left side of the equation.

Add $8 x$ to both sides of the equation.

$40 - 8 x + 8 x = 40$

Combine the opposite terms in $40 - 8 x + 8 x$ .

Add $- 8 x$ and $8 x$ .

$40 + 0 = 40$

Add $40$ and $0$ .

$40 = 40$

Since $40 = 40$ , the equation will always be true for any value of $x$ .

All real numbers

The result can be shown in multiple forms.

All real numbers

Interval Notation:

$(- \infty, \infty)$