Solve for x -(-4x-1)-6/5x=4/5x-1

$- (- 4 x - 1) - \frac{6}{5} x = \frac{4}{5} x - 1$

Simplify $- (- 4 x - 1) - \frac{6}{5} x$ .

Simplify each term.

Apply the distributive property.

$- (- 4 x) - - 1 - \frac{6}{5} x = \frac{4}{5} x - 1$

Multiply $- 4$ by $- 1$ .

$4 x - - 1 - \frac{6}{5} x = \frac{4}{5} x - 1$

Multiply $- 1$ by $- 1$ .

$4 x + 1 - \frac{6}{5} x = \frac{4}{5} x - 1$

Combine $x$ and $\frac{6}{5}$ .

$4 x + 1 - \frac{x \cdot 6}{5} = \frac{4}{5} x - 1$

Move $6$ to the left of $x$ .

$4 x + 1 - \frac{6 x}{5} = \frac{4}{5} x - 1$

To write $4 x$ as a fraction with a common denominator, multiply by $\frac{5}{5}$ .

$4 x \cdot \frac{5}{5} - \frac{6 x}{5} + 1 = \frac{4}{5} x - 1$

Simplify terms.

Combine $4 x$ and $\frac{5}{5}$ .

$\frac{4 x \cdot 5}{5} - \frac{6 x}{5} + 1 = \frac{4}{5} x - 1$

Combine the numerators over the common denominator.

$\frac{4 x \cdot 5 - 6 x}{5} + 1 = \frac{4}{5} x - 1$

Simplify the numerator.

Factor $2 x$ out of $4 x \cdot 5 - 6 x$ .

Factor $2 x$ out of $4 x \cdot 5$ .

$\frac{2 x (2 \cdot 5) - 6 x}{5} + 1 = \frac{4}{5} x - 1$

Factor $2 x$ out of $- 6 x$ .

$\frac{2 x (2 \cdot 5) + 2 x (- 3)}{5} + 1 = \frac{4}{5} x - 1$

Factor $2 x$ out of $2 x (2 \cdot 5) + 2 x (- 3)$ .

$\frac{2 x (2 \cdot 5 - 3)}{5} + 1 = \frac{4}{5} x - 1$

Multiply $2$ by $5$ .

$\frac{2 x (10 - 3)}{5} + 1 = \frac{4}{5} x - 1$

Subtract $3$ from $10$ .

$\frac{2 x \cdot 7}{5} + 1 = \frac{4}{5} x - 1$

Multiply $7$ by $2$ .

$\frac{14 x}{5} + 1 = \frac{4}{5} x - 1$

Combine $\frac{4}{5}$ and $x$ .

$\frac{14 x}{5} + 1 = \frac{4 x}{5} - 1$

Move all terms containing $x$ to the left side of the equation.

Subtract $\frac{4 x}{5}$ from both sides of the equation.

$\frac{14 x}{5} + 1 - \frac{4 x}{5} = - 1$

Combine the numerators over the common denominator.

$1 + \frac{14 x - 4 x}{5} = - 1$

Subtract $4 x$ from $14 x$ .

$1 + \frac{10 x}{5} = - 1$

Cancel the common factor of $10$ and $5$ .

Factor $5$ out of $10 x$ .

$1 + \frac{5 (2 x)}{5} = - 1$

Cancel the common factors.

Factor $5$ out of $5$ .

$1 + \frac{5 (2 x)}{5 (1)} = - 1$

Cancel the common factor.

$1 + \frac{5 (2 x)}{5 \cdot 1} = - 1$

Rewrite the expression.

$1 + \frac{2 x}{1} = - 1$

Divide $2 x$ by $1$ .

$1 + 2 x = - 1$

Move all terms not containing $x$ to the right side of the equation.

Subtract $1$ from both sides of the equation.

$2 x = - 1 - 1$

Subtract $1$ from $- 1$ .

$2 x = - 2$

Divide each term in $2 x = - 2$ by $2$ and simplify.

Divide each term in $2 x = - 2$ by $2$ .

$\frac{2 x}{2} = \frac{- 2}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x}{2} = \frac{- 2}{2}$

Divide $x$ by $1$ .

$x = \frac{- 2}{2}$

Simplify the right side.

Divide $- 2$ by $2$ .

$x = - 1$

Solve for x -(-4x-1)-6/5x=4/5x-1

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