Solve for x 4x-12<=16+8x

$4 x - 12 \leq 16 + 8 x$

Step 1

Move all terms containing $x$ to the left side of the inequality.

Subtract $8 x$ from both sides of the inequality.

$4 x - 12 - 8 x \leq 16$

Subtract $8 x$ from $4 x$ .

$- 4 x - 12 \leq 16$

Step 2

Move all terms not containing $x$ to the right side of the inequality.

Add $12$ to both sides of the inequality.

$- 4 x \leq 16 + 12$

Add $16$ and $12$ .

$- 4 x \leq 28$

Step 3

Divide each term in $- 4 x \leq 28$ by $- 4$ and simplify.

Divide each term in $- 4 x \leq 28$ by $- 4$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- 4 x}{- 4} \geq \frac{28}{- 4}$

Simplify the left side.

Cancel the common factor of $- 4$ .

Cancel the common factor.

$\frac{- 4 x}{- 4} \geq \frac{28}{- 4}$

Divide $x$ by $1$ .

$x \geq \frac{28}{- 4}$

Simplify the right side.

Divide $28$ by $- 4$ .

$x \geq - 7$

Step 4

The result can be shown in multiple forms.

Inequality Form:

$x \geq - 7$

Interval Notation:

$[- 7, \infty)$

Solve for x 4x-12<=16+8x

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