Solve for x (4x+16)/12=x-4

$\frac{4 x + 16}{12} = x - 4$

Cancel the common factor of $4 x + 16$ and $12$ .

Factor $4$ out of $4 x$ .

$\frac{4 (x) + 16}{12} = x - 4$

Factor $4$ out of $16$ .

$\frac{4 x + 4 \cdot 4}{12} = x - 4$

Factor $4$ out of $4 x + 4 \cdot 4$ .

$\frac{4 (x + 4)}{12} = x - 4$

Cancel the common factors.

Factor $4$ out of $12$ .

$\frac{4 (x + 4)}{4 (3)} = x - 4$

Cancel the common factor.

$\frac{4 (x + 4)}{4 \cdot 3} = x - 4$

Rewrite the expression.

$\frac{x + 4}{3} = x - 4$

Multiply both sides by $3$ .

$\frac{x + 4}{3} \cdot 3 = (x - 4) \cdot 3$

Simplify.

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{x + 4}{3} \cdot 3 = (x - 4) \cdot 3$

Rewrite the expression.

$x + 4 = (x - 4) \cdot 3$

Simplify the right side.

Simplify $(x - 4) \cdot 3$ .

Apply the distributive property.

$x + 4 = x \cdot 3 - 4 \cdot 3$

Simplify the expression.

Move $3$ to the left of $x$ .

$x + 4 = 3 \cdot x - 4 \cdot 3$

Multiply $- 4$ by $3$ .

$x + 4 = 3 x - 12$

Solve for $x$ .

Move all terms containing $x$ to the left side of the equation.

Subtract $3 x$ from both sides of the equation.

$x + 4 - 3 x = - 12$

Subtract $3 x$ from $x$ .

$- 2 x + 4 = - 12$

Move all terms not containing $x$ to the right side of the equation.

Subtract $4$ from both sides of the equation.

$- 2 x = - 12 - 4$

Subtract $4$ from $- 12$ .

$- 2 x = - 16$

Divide each term in $- 2 x = - 16$ by $- 2$ and simplify.

Divide each term in $- 2 x = - 16$ by $- 2$ .

$\frac{- 2 x}{- 2} = \frac{- 16}{- 2}$

Simplify the left side.

Cancel the common factor of $- 2$ .

Cancel the common factor.

$\frac{- 2 x}{- 2} = \frac{- 16}{- 2}$

Divide $x$ by $1$ .

$x = \frac{- 16}{- 2}$

Simplify the right side.

Divide $- 16$ by $- 2$ .

$x = 8$

Solve for x (4x+16)/12=x-4

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