Solve for x 4x+2(2x-3)=8(x-1)

$4 x + 2 (2 x - 3) = 8 (x - 1)$

Simplify $4 x + 2 (2 x - 3)$ .

Simplify each term.

Apply the distributive property.

$4 x + 2 (2 x) + 2 \cdot - 3 = 8 (x - 1)$

Multiply $2$ by $2$ .

$4 x + 4 x + 2 \cdot - 3 = 8 (x - 1)$

Multiply $2$ by $- 3$ .

$4 x + 4 x - 6 = 8 (x - 1)$

Add $4 x$ and $4 x$ .

$8 x - 6 = 8 (x - 1)$

Simplify $8 (x - 1)$ .

Apply the distributive property.

$8 x - 6 = 8 x + 8 \cdot - 1$

Multiply $8$ by $- 1$ .

$8 x - 6 = 8 x - 8$

Move all terms containing $x$ to the left side of the equation.

Subtract $8 x$ from both sides of the equation.

$8 x - 6 - 8 x = - 8$

Combine the opposite terms in $8 x - 6 - 8 x$ .

Subtract $8 x$ from $8 x$ .

$0 - 6 = - 8$

Subtract $6$ from $0$ .

$- 6 = - 8$

Since $- 6 \neq - 8$ , there are no solutions.

No solution