Solve for x 4x^2-4x=-4x+1

$4 x^{2} - 4 x = - 4 x + 1$

Step 1

Move all terms containing $x$ to the left side of the equation.

Add $4 x$ to both sides of the equation.

$4 x^{2} - 4 x + 4 x = 1$

Combine the opposite terms in $4 x^{2} - 4 x + 4 x$ .

Add $- 4 x$ and $4 x$ .

$4 x^{2} + 0 = 1$

Add $4 x^{2}$ and $0$ .

$4 x^{2} = 1$

Step 2

Divide each term in $4 x^{2} = 1$ by $4$ and simplify.

Divide each term in $4 x^{2} = 1$ by $4$ .

$\frac{4 x^{2}}{4} = \frac{1}{4}$

Simplify the left side.

Cancel the common factor of $4$ .

Cancel the common factor.

$\frac{4 x^{2}}{4} = \frac{1}{4}$

Divide $x^{2}$ by $1$ .

$x^{2} = \frac{1}{4}$

Step 3

Take the square root of both sides of the equation to eliminate the exponent on the left side.

$x = \pm \sqrt{\frac{1}{4}}$

Step 4

Simplify $\pm \sqrt{\frac{1}{4}}$ .

Rewrite $\sqrt{\frac{1}{4}}$ as $\frac{\sqrt{1}}{\sqrt{4}}$ .

$x = \pm \frac{\sqrt{1}}{\sqrt{4}}$

Any root of $1$ is $1$ .

$x = \pm \frac{1}{\sqrt{4}}$

Simplify the denominator.

Rewrite $4$ as $2^{2}$ .

$x = \pm \frac{1}{\sqrt{2^{2}}}$

Pull terms out from under the radical, assuming positive real numbers.

$x = \pm \frac{1}{2}$

Step 5

The complete solution is the result of both the positive and negative portions of the solution.

First, use the positive value of the $\pm$ to find the first solution.

$x = \frac{1}{2}$

Next, use the negative value of the $\pm$ to find the second solution.

$x = - \frac{1}{2}$

The complete solution is the result of both the positive and negative portions of the solution.

$x = \frac{1}{2}, - \frac{1}{2}$

Step 6

The result can be shown in multiple forms.

Exact Form:

$x = \frac{1}{2}, - \frac{1}{2}$

Decimal Form:

$x = 0.5, - 0.5$

Solve for x 4x^2-4x=-4x+1

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