Solve for x 4x^2-9x+3=0

$4 x^{2} - 9 x + 3 = 0$

Step 1

Use the quadratic formula to find the solutions.

$\frac{- b \pm \sqrt{b^{2} - 4 (a c)}}{2 a}$

Step 2

Substitute the values $a = 4$ , $b = - 9$ , and $c = 3$ into the quadratic formula and solve for $x$ .

$\frac{9 \pm \sqrt{{(- 9)}^{2} - 4 \cdot (4 \cdot 3)}}{2 \cdot 4}$

Step 3

Simplify.

Simplify the numerator.

Raise $- 9$ to the power of $2$ .

$x = \frac{9 \pm \sqrt{81 - 4 \cdot 4 \cdot 3}}{2 \cdot 4}$

Multiply $- 4 \cdot 4 \cdot 3$ .

Multiply $- 4$ by $4$ .

$x = \frac{9 \pm \sqrt{81 - 16 \cdot 3}}{2 \cdot 4}$

Multiply $- 16$ by $3$ .

$x = \frac{9 \pm \sqrt{81 - 48}}{2 \cdot 4}$

Subtract $48$ from $81$ .

$x = \frac{9 \pm \sqrt{33}}{2 \cdot 4}$

Multiply $2$ by $4$ .

$x = \frac{9 \pm \sqrt{33}}{8}$

Step 4

The final answer is the combination of both solutions.

$x = \frac{9 + \sqrt{33}}{8}, \frac{9 - \sqrt{33}}{8}$

Step 5

The result can be shown in multiple forms.

Exact Form:

$x = \frac{9 + \sqrt{33}}{8}, \frac{9 - \sqrt{33}}{8}$

Decimal Form:

$x = 1.84307033 \dots, 0.40692966 \dots$