Solve for x 4x+3<3x+6

$4 x + 3 < 3 x + 6$

Step 1

Move all terms containing $x$ to the left side of the inequality.

Subtract $3 x$ from both sides of the inequality.

$4 x + 3 - 3 x < 6$

Subtract $3 x$ from $4 x$ .

$x + 3 < 6$

Step 2

Move all terms not containing $x$ to the right side of the inequality.

Subtract $3$ from both sides of the inequality.

$x < 6 - 3$

Subtract $3$ from $6$ .

$x < 3$

Step 3

The result can be shown in multiple forms.

Inequality Form:

$x < 3$

Interval Notation:

$(- \infty, 3)$