Solve for x 4x+3(4x+7)=4(7x+3)-3

$4 x + 3 (4 x + 7) = 4 (7 x + 3) - 3$

Simplify $4 x + 3 (4 x + 7)$ .

Simplify each term.

Apply the distributive property.

$4 x + 3 (4 x) + 3 \cdot 7 = 4 (7 x + 3) - 3$

Multiply $4$ by $3$ .

$4 x + 12 x + 3 \cdot 7 = 4 (7 x + 3) - 3$

Multiply $3$ by $7$ .

$4 x + 12 x + 21 = 4 (7 x + 3) - 3$

Add $4 x$ and $12 x$ .

$16 x + 21 = 4 (7 x + 3) - 3$

Simplify $4 (7 x + 3) - 3$ .

Simplify each term.

Apply the distributive property.

$16 x + 21 = 4 (7 x) + 4 \cdot 3 - 3$

Multiply $7$ by $4$ .

$16 x + 21 = 28 x + 4 \cdot 3 - 3$

Multiply $4$ by $3$ .

$16 x + 21 = 28 x + 12 - 3$

Subtract $3$ from $12$ .

$16 x + 21 = 28 x + 9$

Move all terms containing $x$ to the left side of the equation.

Subtract $28 x$ from both sides of the equation.

$16 x + 21 - 28 x = 9$

Subtract $28 x$ from $16 x$ .

$- 12 x + 21 = 9$

Move all terms not containing $x$ to the right side of the equation.

Subtract $21$ from both sides of the equation.

$- 12 x = 9 - 21$

Subtract $21$ from $9$ .

$- 12 x = - 12$

Divide each term in $- 12 x = - 12$ by $- 12$ and simplify.

Divide each term in $- 12 x = - 12$ by $- 12$ .

$\frac{- 12 x}{- 12} = \frac{- 12}{- 12}$

Simplify the left side.

Cancel the common factor of $- 12$ .

Cancel the common factor.

$\frac{- 12 x}{- 12} = \frac{- 12}{- 12}$

Divide $x$ by $1$ .

$x = \frac{- 12}{- 12}$

Simplify the right side.

Divide $- 12$ by $- 12$ .

$x = 1$