Solve for x (4x)/3-5y=11

$\frac{4 x}{3} - 5 y = 11$

Step 1

Add $5 y$ to both sides of the equation.

$\frac{4 x}{3} = 11 + 5 y$

Step 2

Multiply both sides of the equation by $\frac{3}{4}$ .

$\frac{3}{4} \cdot \frac{4 x}{3} = \frac{3}{4} (11 + 5 y)$

Step 3

Simplify both sides of the equation.

Simplify the left side.

Simplify $\frac{3}{4} \cdot \frac{4 x}{3}$ .

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3}{4} \cdot \frac{4 x}{3} = \frac{3}{4} (11 + 5 y)$

Rewrite the expression.

$\frac{1}{4} (4 x) = \frac{3}{4} (11 + 5 y)$

Cancel the common factor of $4$ .

Factor $4$ out of $4 x$ .

$\frac{1}{4} (4 (x)) = \frac{3}{4} (11 + 5 y)$

Cancel the common factor.

$\frac{1}{4} (4 x) = \frac{3}{4} (11 + 5 y)$

Rewrite the expression.

$x = \frac{3}{4} (11 + 5 y)$

Simplify the right side.

Simplify $\frac{3}{4} (11 + 5 y)$ .

Apply the distributive property.

$x = \frac{3}{4} \cdot 11 + \frac{3}{4} (5 y)$

Multiply $\frac{3}{4} \cdot 11$ .

Combine $\frac{3}{4}$ and $11$ .

$x = \frac{3 \cdot 11}{4} + \frac{3}{4} (5 y)$

Multiply $3$ by $11$ .

$x = \frac{33}{4} + \frac{3}{4} (5 y)$

Multiply $\frac{3}{4} (5 y)$ .

Combine $5$ and $\frac{3}{4}$ .

$x = \frac{33}{4} + \frac{5 \cdot 3}{4} y$

Multiply $5$ by $3$ .

$x = \frac{33}{4} + \frac{15}{4} y$

Combine $\frac{15}{4}$ and $y$ .

$x = \frac{33}{4} + \frac{15 y}{4}$

Step 4

Reorder $\frac{33}{4}$ and $\frac{15 y}{4}$ .

$x = \frac{15 y}{4} + \frac{33}{4}$