Solve for x 4x-3-7(x+1)=-6x+5

$4 x - 3 - 7 (x + 1) = - 6 x + 5$

Step 1

Simplify $4 x - 3 - 7 (x + 1)$ .

Simplify each term.

Apply the distributive property.

$4 x - 3 - 7 x - 7 \cdot 1 = - 6 x + 5$

Multiply $- 7$ by $1$ .

$4 x - 3 - 7 x - 7 = - 6 x + 5$

Simplify by adding terms.

Subtract $7 x$ from $4 x$ .

$- 3 x - 3 - 7 = - 6 x + 5$

Subtract $7$ from $- 3$ .

$- 3 x - 10 = - 6 x + 5$

Step 2

Move all terms containing $x$ to the left side of the equation.

Add $6 x$ to both sides of the equation.

$- 3 x - 10 + 6 x = 5$

Add $- 3 x$ and $6 x$ .

$3 x - 10 = 5$

Step 3

Move all terms not containing $x$ to the right side of the equation.

Add $10$ to both sides of the equation.

$3 x = 5 + 10$

Add $5$ and $10$ .

$3 x = 15$

Step 4

Divide each term in $3 x = 15$ by $3$ and simplify.

Divide each term in $3 x = 15$ by $3$ .

$\frac{3 x}{3} = \frac{15}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 x}{3} = \frac{15}{3}$

Divide $x$ by $1$ .

$x = \frac{15}{3}$

Simplify the right side.

Divide $15$ by $3$ .

$x = 5$