Solve for x 4x^3=92

$4 x^{3} = 92$

Step 1

Subtract $92$ from both sides of the equation.

$4 x^{3} - 92 = 0$

Step 2

Factor $4$ out of $4 x^{3} - 92$ .

Factor $4$ out of $4 x^{3}$ .

$4 (x^{3}) - 92 = 0$

Factor $4$ out of $- 92$ .

$4 x^{3} + 4 \cdot - 23 = 0$

Factor $4$ out of $4 x^{3} + 4 \cdot - 23$ .

$4 (x^{3} - 23) = 0$

Step 3

Divide each term in $4 (x^{3} - 23) = 0$ by $4$ and simplify.

Divide each term in $4 (x^{3} - 23) = 0$ by $4$ .

$\frac{4 (x^{3} - 23)}{4} = \frac{0}{4}$

Simplify the left side.

Cancel the common factor of $4$ .

Cancel the common factor.

$\frac{4 (x^{3} - 23)}{4} = \frac{0}{4}$

Divide $x^{3} - 23$ by $1$ .

$x^{3} - 23 = \frac{0}{4}$

Simplify the right side.

Divide $0$ by $4$ .

$x^{3} - 23 = 0$

Step 4

Add $23$ to both sides of the equation.

$x^{3} = 23$

Step 5

Take the cube root of both sides of the equation to eliminate the exponent on the left side.

$x = \sqrt[3]{23}$

Step 6

The result can be shown in multiple forms.

Exact Form:

$x = \sqrt[3]{23}$

Decimal Form:

$x = 2.84386697 \dots$