Solve for x 4x-3x-1=7

$4 x - 3 x - 1 = 7$

Subtract $3 x$ from $4 x$ .

$x - 1 = 7$

Move all terms not containing $x$ to the right side of the equation.

Add $1$ to both sides of the equation.

$x = 7 + 1$

Add $7$ and $1$ .

$x = 8$

$x = 8$

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