Solve for x 4x+5(3+x)=87

$4 x + 5 (3 + x) = 87$

Step 1

Simplify $4 x + 5 (3 + x)$ .

Simplify each term.

Apply the distributive property.

$4 x + 5 \cdot 3 + 5 x = 87$

Multiply $5$ by $3$ .

$4 x + 15 + 5 x = 87$

Add $4 x$ and $5 x$ .

$9 x + 15 = 87$

Step 2

Move all terms not containing $x$ to the right side of the equation.

Subtract $15$ from both sides of the equation.

$9 x = 87 - 15$

Subtract $15$ from $87$ .

$9 x = 72$

Step 3

Divide each term in $9 x = 72$ by $9$ and simplify.

Divide each term in $9 x = 72$ by $9$ .

$\frac{9 x}{9} = \frac{72}{9}$

Simplify the left side.

Cancel the common factor of $9$ .

Cancel the common factor.

$\frac{9 x}{9} = \frac{72}{9}$

Divide $x$ by $1$ .

$x = \frac{72}{9}$

Simplify the right side.

Divide $72$ by $9$ .

$x = 8$