Solve for x (-4x+5)-(6x+7)=0

$(- 4 x + 5) - (6 x + 7) = 0$

Simplify $- 4 x + 5 - (6 x + 7)$ .

Simplify each term.

Apply the distributive property.

$- 4 x + 5 - (6 x) - 1 \cdot 7 = 0$

Multiply $6$ by $- 1$ .

$- 4 x + 5 - 6 x - 1 \cdot 7 = 0$

Multiply $- 1$ by $7$ .

$- 4 x + 5 - 6 x - 7 = 0$

$- 4 x + 5 - 6 x - 7 = 0$

Simplify by adding terms.

Subtract $6 x$ from $- 4 x$ .

$- 10 x + 5 - 7 = 0$

Subtract $7$ from $5$ .

$- 10 x - 2 = 0$

$- 10 x - 2 = 0$

$- 10 x - 2 = 0$

Add $2$ to both sides of the equation.

$- 10 x = 2$

Divide each term in $- 10 x = 2$ by $- 10$ and simplify.

Divide each term in $- 10 x = 2$ by $- 10$ .

$\frac{- 10 x}{- 10} = \frac{2}{- 10}$

Simplify the left side.

Cancel the common factor of $- 10$ .

Cancel the common factor.

$\frac{- 10 x}{- 10} = \frac{2}{- 10}$

Divide $x$ by $1$ .

$x = \frac{2}{- 10}$

$x = \frac{2}{- 10}$

$x = \frac{2}{- 10}$

Simplify the right side.

Cancel the common factor of $2$ and $- 10$ .

Factor $2$ out of $2$ .

$x = \frac{2 (1)}{- 10}$

Cancel the common factors.

Factor $2$ out of $- 10$ .

$x = \frac{2 \cdot 1}{2 \cdot - 5}$

Cancel the common factor.

$x = \frac{2 \cdot 1}{2 \cdot - 5}$

Rewrite the expression.

$x = \frac{1}{- 5}$

$x = \frac{1}{- 5}$

$x = \frac{1}{- 5}$

Move the negative in front of the fraction.

$x = - \frac{1}{5}$

$x = - \frac{1}{5}$

$x = - \frac{1}{5}$

The result can be shown in multiple forms.

Exact Form:

$x = - \frac{1}{5}$

Decimal Form:

$x = - 0.2$

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