Solve for x 4x-5=x-5+3x

$4 x - 5 = x - 5 + 3 x$

Since $x$ is on the right side of the equation, switch the sides so it is on the left side of the equation.

$x - 5 + 3 x = 4 x - 5$

Add $x$ and $3 x$ .

$4 x - 5 = 4 x - 5$

Move all terms containing $x$ to the left side of the equation.

Subtract $4 x$ from both sides of the equation.

$4 x - 5 - 4 x = - 5$

Combine the opposite terms in $4 x - 5 - 4 x$ .

Subtract $4 x$ from $4 x$ .

$0 - 5 = - 5$

Subtract $5$ from $0$ .

$- 5 = - 5$

Since $- 5 = - 5$ , the equation will always be true for any value of $x$ .

All real numbers

The result can be shown in multiple forms.

All real numbers

Interval Notation:

$(- \infty, \infty)$