Solve for x (4x+6)/2=(3x-15)/3

$\frac{4 x + 6}{2} = \frac{3 x - 15}{3}$

Step 1

Cancel the common factor of $4 x + 6$ and $2$ .

Factor $2$ out of $4 x$ .

$\frac{2 (2 x) + 6}{2} = \frac{3 x - 15}{3}$

Factor $2$ out of $6$ .

$\frac{2 (2 x) + 2 \cdot 3}{2} = \frac{3 x - 15}{3}$

Factor $2$ out of $2 (2 x) + 2 (3)$ .

$\frac{2 (2 x + 3)}{2} = \frac{3 x - 15}{3}$

Cancel the common factors.

Factor $2$ out of $2$ .

$\frac{2 (2 x + 3)}{2 (1)} = \frac{3 x - 15}{3}$

Cancel the common factor.

$\frac{2 (2 x + 3)}{2 \cdot 1} = \frac{3 x - 15}{3}$

Rewrite the expression.

$\frac{2 x + 3}{1} = \frac{3 x - 15}{3}$

Divide $2 x + 3$ by $1$ .

$2 x + 3 = \frac{3 x - 15}{3}$

Step 2

Solve for $x$ .

Cancel the common factor of $3 x - 15$ and $3$ .

Factor $3$ out of $3 x$ .

$2 x + 3 = \frac{3 (x) - 15}{3}$

Factor $3$ out of $- 15$ .

$2 x + 3 = \frac{3 (x) + 3 \cdot - 5}{3}$

Factor $3$ out of $3 (x) + 3 (- 5)$ .

$2 x + 3 = \frac{3 (x - 5)}{3}$

Cancel the common factors.

Factor $3$ out of $3$ .

$2 x + 3 = \frac{3 (x - 5)}{3 (1)}$

Cancel the common factor.

$2 x + 3 = \frac{3 (x - 5)}{3 \cdot 1}$

Rewrite the expression.

$2 x + 3 = \frac{x - 5}{1}$

Divide $x - 5$ by $1$ .

$2 x + 3 = x - 5$

Solve for $x$ .

Move all terms containing $x$ to the left side of the equation.

Subtract $x$ from both sides of the equation.

$2 x + 3 - x = - 5$

Subtract $x$ from $2 x$ .

$x + 3 = - 5$

Move all terms not containing $x$ to the right side of the equation.

Subtract $3$ from both sides of the equation.

$x = - 5 - 3$

Subtract $3$ from $- 5$ .

$x = - 8$

Solve for x (4x+6)/2=(3x-15)/3

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