Solve for x 4x-8=6x+12

$4 x - 8 = 6 x + 12$

Step 1

Move all terms containing $x$ to the left side of the equation.

Subtract $6 x$ from both sides of the equation.

$4 x - 8 - 6 x = 12$

Subtract $6 x$ from $4 x$ .

$- 2 x - 8 = 12$

Step 2

Move all terms not containing $x$ to the right side of the equation.

Add $8$ to both sides of the equation.

$- 2 x = 12 + 8$

Add $12$ and $8$ .

$- 2 x = 20$

Step 3

Divide each term in $- 2 x = 20$ by $- 2$ and simplify.

Divide each term in $- 2 x = 20$ by $- 2$ .

$\frac{- 2 x}{- 2} = \frac{20}{- 2}$

Simplify the left side.

Cancel the common factor of $- 2$ .

Cancel the common factor.

$\frac{- 2 x}{- 2} = \frac{20}{- 2}$

Divide $x$ by $1$ .

$x = \frac{20}{- 2}$

Simplify the right side.

Divide $20$ by $- 2$ .

$x = - 10$